Calculus Questions on trigonometry
Fill in the blank.The
2 cos x − 1 = 0 is given by
x =
π |
3 |
x =
5π |
3 |
n is an integer.
2.LarPreCalcRMRPAlt6 6.3.002.My Notes
Question Part |
Points |
Submissions Used |
Fill in the blank.
The equation tan2(x) – 5 tan(x) + 6 = 0 is an equation of type.
3.–/0.41 pointsLarPreCalcRMRPAlt6 6.3.003.My Notes
Is x = 0
a solution of the equation
cos x = 0?
4.–/0.41 pointsLarPreCalcRMRPAlt6 6.3.004.My Notes
To solve sec x sin2 x = sec x,
do you divide each side by
sec x?
5.–/0.41 pointsLarPreCalcRMRPAlt6 6.3.008.My Notes
Verify that the x-values are solutions of the equation.14 cos2 2x − 7 = 0
(a)x =
π |
8 |
14 cos2
|
= | 14 cos2
|
||||||||||
= | − 7 | |||||||||||
= | 0 |
(b)
x =
3π |
8 |
14 cos2
|
= | 14 cos2
|
|||||||||||
= | − 7 | ||||||||||||
= | 0 |
6.–/0.41 pointsLarPreCalcRMRPAlt6 6.3.014.My Notes
Find all solutions of the equation in the interval [0°, 360°). (Enter your answers from smallest to largest.)
x =
°
x =
°
7.–/0.41 pointsLarPreCalcRMRPAlt6 6.3.016.My Notes
Find all solutions of the equation in the interval [0°, 360°). (Enter your answers from smallest to largest.)
x =
°
x =
°
8.–/0.41 pointsLarPreCalcRMRPAlt6 6.3.018.My Notes
Find all solutions of the equation in the interval [0, 2π). (Write your answer in terms of π. Enter your answers from smallest to largest.)
x =
radians
x =
radians
9.–/0.41 pointsLarPreCalcRMRPAlt6 6.3.022.My Notes
Find all solutions of the equation in the interval [0, 2π).cos x =
1 |
2 |
x = (smaller x-value) |
x = (larger x-value) |
10.–/0.41 pointsLarPreCalcRMRPAlt6 6.3.026.My Notes
Find all solutions of the equation in the interval [0, 2π).sec x = 2
x = (smaller x-value) |
x = (larger x-value) |
11.LarPreCalcRMRPAlt6 6.3.030.My Notes
Question Part |
Points |
Submissions Used |
Solve the equation for x. Use n as an integer constant.
x =
(smaller value for a given
n)
x =
(larger value for a given
n)
12.LarPreCalcRMRPAlt6 6.3.034.My Notes
Question Part |
Points |
Submissions Used |
Solve the equation. (Use n as an integer constant. Enter your response in radians.)3 cot2(x) − 1 = 0
x =
(smaller value) |
x =
(larger value) |