confidence interval and interpretation, statistics homework help

A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of

5.07 hours, with a standard deviation of 2.46 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.03 hours, with a standard deviation of 1.99 hours. Construct and interpret a 95​% confidence interval for the mean difference in leisure time between adults with no children and adults with children. (μ1−μ2).

Let μrepresent the mean leisure hours of adults with no children under the age of 18 and μrepresent the mean leisure hours of adults with children under the age of 18. The 95​% confidence interval for 1μ2is the range from __ hours to __ hours.

(Round to two decimal places as needed.)

What is the interpretation of this confidence​ interval?

There is a __% 
probability that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours.

There is a __

probability that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours.



There is __% 
 
confidence that the difference of the means is in the interval. Conclude that there is 

significant difference in the number of leisure hours.

There is __% 
 
confidence that the difference of the means is in the interval. Conclude that there is 
insufficient evidence of  insufficient evidence of a 
significant difference in the number of leisure hours.